Question 1 of 1Mark for Review 🏳️Cross-out(ax+3)(5x2−bx+4)=20x3−9x2−2x+12(ax + 3)(5x^2 - bx + 4) = 20x^3 - 9x^2 - 2x + 12(ax+3)(5x2−bx+4)=20x3−9x2−2x+12 The equation above is true for all xxx, where aaa and bbb are constants. What is the value of ababab?A18B20C24D40